ExamPlay Dark Logo
সাইন ইন করুন

JEE MAIN - Physics (2021 - 18th March Morning Shift - No. 27)

What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature T? (kB is Boltzmann constant)
$${1 \over 2}{k_B}T$$
$${2 \over 3}{k_B}T$$
$${3 \over 2}{k_B}T$$
$${k_B}T$$

ব্যাখ্যা

Energy associated with each digress of freedom is $${1 \over 2}{k_B}T$$.

মন্তব্য (0)

মন্তব্য লগইন করুন
বিজ্ঞাপন
BrainBehindX Inc Logo
©2026; দ্বারা চালিত BrainBehindX Inc